Find the center, transverse axis, vertices, foci, and asymptotes for the hyperbolaCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge andAnswer by Fombitz () ( Show Source ) You can put this solution on YOUR website!
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(x-2)^2+(y+1)^2=9 graph
(x-2)^2+(y+1)^2=9 graph-A sphere is the graph of an equation of the form x 2 y 2 z 2 = p 2 for some real number p The radius of the sphere is p (see the figure below) Ellipsoids are the graphs of equations of the form ax 2 by 2 cz 2 = p 2, where a, b, and c are all positiveFormula for love X^2(ysqrt(x^2))^2=1 (wolframalphacom) 2 points by carusen on Feb 14, 11 hide past favorite 41 comments ck2 on Feb 14, 11
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How To Given the standard form of an equation for an ellipse centered at (0,0) ( 0, 0), sketch the graph Use the standard forms of the equations of an ellipse to determine the major axis, vertices, covertices, and foci If the equation is in the form x2 a2 y2 b2 = 1 x 2 a 2 y 2 b 2 = 1May 03, 14 · x 2 /4 y 2 /9 = 1 The equation is y 2 /9 x 2 /4 = 1 The standard form of the equation of an ellipse center (h, k) with major and minor axes of lengths 2 2 (y k ) 2 /b 2 = 1 or (x h) 2 /b 2 (y k) 2 /a 2 = 1The vertices and foci lie on the major axis, a and c units, respectively, from the center (h, k ) and the relation between a, bCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
I am already using it and I only can plot in 2 dimensional graph Can someone help me with this problem?Graph {eq}(x 2)^2 (y 1)^2 = 9 {/eq} Circles A circle is a two dimensional relationship for which every point is equally distant from the point in the centerEvery line through the center is a line of symmetry The yaxis and the xaxis are lines of symmetry ( my choice) Every line through the center is a line of symmetry The yaxis and the xaxis are lines of symmetry 2 Graph
Substitute x=2y into x^2y^2=9, to give (2y)^2y^2=9 Expand the brackets using FOIL to give 44yy^2y^2=9 By grouping like terms together get 2y^24y5=0 Because the question asks for the answer in 2dp, you know to use the quadratic formula, so substitute into the given formula where a=2, b=4 and c=5 (dont forget the minus sign!)It's the equation of sphere The general equation of sphere looks like math(xx_0)^2(yy_0)^2(zz_0)^2=a^2/math Wheremath (x_0,y_0,z_0)/math is the centre of the circle and matha /math is the radious of the circle It's graph looksThat's a circle Compare mathx^2y^22x=0/math with the general equation of a circle mathx^2y^22gx2fyc=0/math and write down the values of the constants
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Plotting graphics3d Share Improve this question Follow asked Nov 29 '15 at 533 user userThe graph of mathx^2(y\sqrt3{x^2})^2=1/math is very interesting and is show below using desmosCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
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Popular Problems Algebra Graph x^2y^2=9 x2 y2 = 9 x 2 y 2 = 9 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h h represents the xoffset from the origin, and k k represents the yPreAlgebra Graph x^2y^2=1 x2 − y2 = −1 x 2 y 2 = 1 Find the standard form of the hyperbola Tap for more steps Flip the sign on each term of the equation so the term on the right side is positive − x 2 y 2 = 1 x 2 y 2 = 1 Simplify each term in the equation in order to set the right side equal to 1 1Apr 04, 10 · Favorite Answer (x^ (2))/ (36)y^ (2)=1 Simplify each term in the equation in order to set the righthand side equal to 1 The standard form of an ellipse or hyperbola requires the righthand side of the equation be 1 (x^ (2))/ (36) (y^ (2))/ (1)=1 This is the form of a hyperbola Use this form to determine the values used to find vertices
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Draw The Graph Of 2x Y 1 0 And 2x Y 9 On The Same Graph Use 2 Cm 1 Unit On Both Axes Write Down The
Y2 9 − x2 1 = 1 This is the equation of an updown hyperbola The general equation is (y− k)2 a2 − (x −h)2 b2 = 1 The center is (h, k) = (0,0) The vertices are (h, k± a), A = (0,3) and A' = (0, −3) The slope of the asymptotes are ± a b = ±3 The equations of the asymptotes are y = 3x and y = − 3x To determine the foci, we need c, c2 = a2 b2Algebra Graph x^2 (y2)^2=4 x2 (y − 2)2 = 4 x 2 ( y 2) 2 = 4 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h hThe graph is attached below Stepbystep explanation y – 1 = 2 (x – 2) y1 = 2x 4 add 1 on both sides y = 2x 3 To graph the given equation we make a table Plug in some number for x and find out the value of y x y = 2x3
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historySolve for y Subtract x^ {2} from both sides of the equation Subtract x 2 from both sides of the equation Subtracting x^ {2} from itself leaves 0 Subtracting x 2 from itself leaves 0 Take the square root of both sides of the equation Take the square root of both sides of the equation Subtract \sqrt 3 {x} from both sides of the equationA log–log plot of y = x (blue), y = x2 (green), and y = x3 (red) Note the logarithmic scale markings on each of the axes, and that the log x and log y axes (where the logarithms are 0) are where x and y themselves are 1 In science and engineering, a log–log graph or log–log plot is a twodimensional graph of numerical data that uses
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